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IPL 2018, MI vs SRH: Rohit Sharma won the toss and chose to field first

Speed News Desk | Updated on: 24 April 2018, 19:32 IST
MI vs SRH

 


 

Rohit Sharma won the toss and chose to field first.

Mumbai Indians have won just one match of the five it has played but it could well have been 5 wins off 5 matches had Mumbai been a little luckier. This IPL has seen almost all the matches going till the very last ball and Mumbai has been a part of all those matches. All their losses have been by an inch of hair. The team knows well that they have not done too much wrong and they have been more of unlucky when it came to winning the matches.

Whereas Sunrisers Hyderabad won their first three matches consecutively but have lost their last two matches. SRH’s bowlers set up games beautifully in the first three matches, restricting their opponents to totals under 150. However, in the last couple of games, their bowlers have come in for some tap and SRH has ended up conceding totals of 192 & 182.

Today's match depends much upon the prospects of Shikhar Dhawan's participation. He was injured and hence could not participate in the last match for his team. Whereas Mumbai Indians' story has been the one of that fine line between a win and a loss and it seems Mumbai has been walking that fine line and unfortunately falling on the wrong side everytime. They would indeed like to walk those last steps to the victory.

 

First published: 24 April 2018, 19:32 IST